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Chemistry 17 Online
OpenStudy (anonymous):

Which statement is most likely to be true for astatine, which is below iodine in Group VII of the Periodic Table? A Astatine and aqueous potassium chloride react to form aqueous potassium astatide and chlorine. B Potassium astatide and hot dilute sulphuric acid react to form white fumes of only hydrogen astatide. C Silver astatide reacts with dilute aqueous ammonia in excess to form a solution of a soluble complex. D Sodium astatide and hot concentrated sulphuric acid react to form astatine

OpenStudy (anonymous):

can anyone explain why is it not A or B or C but its D is there any reasoning behind it or is it just pure memorization?

OpenStudy (anonymous):

A is not right because Astatine cannot displace chlorine as it is below chlorine in seventh group umm thats all i got

OpenStudy (anonymous):

Just reviewed my notes and it says AgCl ios soluble, AgBr sparingly soluble and AgI is insolouble in NH3 by following the pattern silver Astatide must be insoluble ion dilute nh3 C is wrong

OpenStudy (anonymous):

*in not ion

OpenStudy (anonymous):

Thankyou!

OpenStudy (anonymous):

:) no problem i got stuck on the same question i just memorised it :p

OpenStudy (anonymous):

Hahah lol, its a confusing question, but you're explanation helped alot

OpenStudy (anonymous):

Oh and for B i just realised that hydrogen astatide cannot be the ionly product sulopher and oxygen has to fit some where so there B is wrong too B|

OpenStudy (anonymous):

Hahaha lol, i did the same for B and was left with C and D so i just chose C xD

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