Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).

Question

pooja195 · Answer

We need to find the slope first

pooja195 · Answer

$$\huge~\frac{ y_2-y_1 }{ x_2-x_1 }$$

pooja195 · Answer

(x1,y1)
(x2,y2)

anonymous · Answer

3/-3

anonymous · Answer

i think?

mathmate · Answer

(x1,y1)=(-3,2)
(x2,y2)=(6,-1)
So (y2-y1)/(x2-x1) = (-1-2)/(6-(-3)) = ?

mathmate · Answer

It is always a good idea to write down the two points one on top of the other, as @pooja195 suggested earlier.
This way, it's easier to figure out the numbers without making a mistake.

anonymous · Answer

3/-3

anonymous · Answer

wait 1/-3

mathmate · Answer

Excellent, so that's your slope, 1/-3 is the same as -1/3.
Now use the point slope form to get the equation.
You can use P1=(x1,y1)=(-3,2) as your point, and slope is a=-1/3.
The equation is then
(y-y1) = a(x-x1)

anonymous · Answer

y= 1/3 x-1?

mathmate · Answer

You are close, but got signs wrong somewhere.

anonymous · Answer

y=-1/3 x+1?

mathmate · Answer

That's it, excellent!
Is everything clear?

anonymous · Answer

yes thank you so much!!

mathmate · Answer

You're welcome!  @pooja195 started you off with the right foot!