Question

Two identical objects each with a charge of +3.0 μC experience a repulsive force of +0.90 N between them. How far apart are the objects?

A. 0.10 m

B. 0.20 m

C. 0.30 m

D. 0.90 m

Answer 1

we have to apply the law of Coulomb
\[F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}\]

Answer 2

ok! what do we plug in? :/

Answer 3

so we can write:
\[d = \sqrt {K\frac{{{Q_1}{Q_2}}}{F}} = \sqrt {9 \times {{10}^9}\frac{{3 \times {{10}^{ - 6}} \times 3 \times {{10}^{ - 6}}}}{{0.9}}} \]

Answer 4

ok! and we get 0.3 ?

Answer 5

and choice C is our solution?

Answer 6

that's right!

Answer 7

yay! thanks!!:)

Answer 8

:)