Question

Two objects, each with a charge of +5.0 × 10^-5 C, are separated by 0.50 m. What is the magnitude and type of force between them?

A. -90 N, attractive

B. -45 N, repulsive

C. +45 N, attractive

D. +90 N, repulsive

Answer 1

please wait a moment

Answer 2

ok!

Answer 3

the force is repulsive, since both charges are positive

Answer 4

ok! so it is either B or D? how can we find out which one?

Answer 5

the magnitude of that force, is given by the Coulomb's law:
\[\large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}} = 9 \times {10^9}\frac{{5 \times {{10}^{ - 5}} \times 5 \times {{10}^{ - 5}}}}{{{{\left( {5 \times {{10}^{ - 1}}} \right)}^2}}}\]

Answer 6

ok! we get 90? so our solution is choice D?

Answer 7

that's right!

Answer 8

yay!! thank you!!

Answer 9

:)