In an electric field of strength 0.50 N/C, a test charge experiences a force of 2.50 × 10^-4 N in the same direction as the field. What is the magnitude of the test charge?

A. -5.00 × 10^-4 C

B. -2.50 × 10^-4 C

C. +2.50 × 10^-4 C

D. +5.00 × 10^-4 C

Question

In an electric field of strength 0.50 N/C, a test charge experiences a force of 2.50 × 10^-4 N in the same direction as the field. What is the magnitude of the test charge?

A.       -5.00 × 10^-4 C

B.       -2.50 × 10^-4 C

C.       +2.50 × 10^-4 C

D.       +5.00 × 10^-4 C

michele_laino · Answer

the requested charge (magnitude) is given by the subsequent formula:
$$\large Q = \frac{F}{E} = \frac{{2.5 \times {{10}^{ - 4}}}}{{0.5}}$$

anonymous · Answer

ok! so we get 5E-4? so our answer is choice D? :O

michele_laino · Answer

that's right! Since vectors E and Q have  the same  orientation
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anonymous · Answer

ahh okie!! yay!! thank you!:)

michele_laino · Answer

vectors E and F

michele_laino · Answer

:)