Question

Write the equation of a line parallel to the line 2x+3y=5 and passes through the point (9,-3)

Answer 1

First get your equation in slope-intercept form: \(y=mx+b\) and m will be your slope. An equation that is parallel to it will have the same slope.

Then just use the point-slope formula: \(\large y-y_1=m(x-x_1)\)

Answer 2

not really sure :/

Answer 3

do you know how to put the equation 2x + 3y = 5 in y = mx + b form ?

Answer 4

Nope :l i am so bad at math lol

Answer 5

2x + 3y = 5.......we are basically solving for y
subtract 2x from both sides
2x - 2x + 3y = -2x + 5
combine like terms
3y = -2x + 5
divide both sides by 3
(3/3)y = (-2/3)x + 5/3
y = -2/3x + 3

read ^^ and see if you have any questions ? Then we will continue....

Answer 6

well.....questions ? or shall we continue ?

Answer 7

hmm i think I'm starting to get it

Answer 8

oops....I meant y = -2/3x + 5/3...I forgot the 5

Answer 9

no worries haha, yea thats a option it shows

Answer 10

so our equation in y = mx + b form is : y = -2/3x + 5/3

In y = mx + b form, the slope is the number in the m position.
So our slope is -2/3
Parallel lines WILL HAVE same slope.

still with me ?

Answer 11

ohhh okay

Answer 12

now we take y = mx + b
slope (m) = -2/3
your points (9,-3)....x = 9 and y = -3
so basically the only thing we need to find is b, the y intercept

y = mx + b
-3 = -2/3(9) + b
-3 = -6 + b
-3 + 6 = b
3 = b

so our parallel equation is : y = -2/3x + 3

Answer 13

we all good ? I tried to explain as best I could, but if you have any questions, I can try to explain better.

Answer 14

Were all good thanks i appreciate it :)