A point charge of +1.0 µC is moved in the direction of an electric field, and it has a change in electric potential difference energy of 10.0 J. What was the change in electric potential difference? 1 µC = 10^-6 C

A. -1.0 × 10^8 V

B. -1.0 × 10^7 V

C. +1.0 × 10^7 V

D. +1.0 × 10^8 V

Question

A point charge of +1.0 µC is moved in the direction of an electric field, and it has a change in electric potential difference energy of 10.0 J. What was the change in electric potential difference? 1 µC = 10^-6 C

A.       -1.0 × 10^8 V

B.       -1.0 × 10^7 V

C.       +1.0 × 10^7 V

D.       +1.0 × 10^8 V

michele_laino · Answer

the requested value is:
$$\Delta V = \frac{L}{q} = \frac{{10}}{{{{10}^{ - 6}}}}$$

anonymous · Answer

ok! so we get 10,000,000? so our solution is choice C?

michele_laino · Answer

the final potential is greter than the initial potential

michele_laino · Answer

yes!

anonymous · Answer

yay! thank you!!:D

michele_laino · Answer

:)