Divide and Simplify this rational expression. MEDAL

Question

theyankee · Answer

attachment

nnesha · Answer

factor (a^2-a) = ?

nnesha · Answer

and change division to multiplication ( multiply top with the reciprocal of the divisor  )
$$\large\rm \frac{ a }{ b } \div  \frac{ c }{ d } = \frac{ a }{ b } \times \frac{ d }{ c}$$

theyankee · Answer

I have a really, really hard time with the parentheses in these problems.  Do they change operations at all?

nnesha · Answer

parentheses those are factor form of quadratic equation

theyankee · Answer

I know, but once it is factored, I have a problem using them in division problems. I'm working on the problem and I'm almost done. Would you check my answer when I'm done?

nnesha · Answer

sure!

theyankee · Answer

Is this it?

theyankee · Answer

(I'm so bad at these ^^;)

nnesha · Answer

how did you get that ?

nnesha · Answer

:-)

theyankee · Answer

After switching around everything I had (A-4)(a+3)/2(a=3) times (a+3)(a-1)/2(a-4).  I cross multiplied 2(a-4) and (a-4)(a=3) to get (a+3)^2 and cross multiplied the other values to get 2(a-1) Then distributed.

nnesha · Answer

so (a-4)(a+3) = (a+3)^2 ?

theyankee · Answer

That's what I got when I multiplied it by 2(a-4) The a-4s cancelled out and that left 2 and a+3. I suppose it could have been 2(a+3,) though.

nnesha · Answer

mhm i'm confused

nnesha · Answer

i just want to know how u got (a+3)^2 ?? :-)

nnesha · Answer

yep right (a-4)s cancels out :-)

theyankee · Answer

I multiplied the value (a-4)(a+3) by 2(a-4). When the a-4s cancelled, I was left with 2 on one side and a+3 on the other. So, re-evaluating, it wouldn't be (a+3)^2 it would be 2(a+3)

theyankee · Answer

I'm might also make a few errors as I'm under a bit of pressure. My test it timing out :(

theyankee · Answer

*is

nnesha · Answer

mhm you got it right *i guess* :|

theyankee · Answer

So this is the correct answer?

nnesha · Answer

http://prntscr.com/7d52sr :-(

nnesha · Answer

i'm sorry but i'm not allowed to help you 'n ur test 
that is for you!

theyankee · Answer

I'm not cheating :( I'm just trying to confirm what I think is right before my test times out. I am trying!

theyankee · Answer

It's an openbook.

theyankee · Answer

If it wasn't open book, I wouldn't ask :( I just have a really hard time understanding.

theyankee · Answer

But if you don't agree, I understand. Thanks anyway :(

nnesha · Answer

openbook ) it's not gonna give u the direct answer 
i'm pretty sure example that is on ur notebook are different from the test

nnesha · Answer

:-) gO_Od luck!