Question

If 4.0 × 10^-18 J of work done on a point charge changes its electric potential difference by 25.0 V, then what is the magnitude of the charge?

A. 1.6 × 10^-19 C

B. 4.0 × 10^-19 C

C. 1.6 × 10^-18 C

D. 4.0 × 10^-18 C

Answer 1

the requested charge (magnitude) is:
\[q = \frac{W}{{\Delta V}}\]

Answer 2

ok! 4.0*10^-18 / 25 ?

Answer 3

\[q = \frac{W}{{\Delta V}} = \frac{{4 \times {{10}^{ - 18}}}}{{25}}\]

Answer 4

yes!

Answer 5

yay! so we get 1.6E-19? so choice A is our solution?

Answer 6

correct!

Answer 7

yay!! thanks!!:D

Answer 8

:)