Easy Statistics, solved some, but need some help too! Thanks!
John is an expert horseshoe thrower who only misses 15% of the time. Choose the expression that correctly represents the probability John will miss fewer than 50 times if he throws 400 horseshoes. normalcdf(-E99,50,60,7.14) normalcdf(50,E99,60,7.14) normalpdf(-E99,50,400,7.14) normalpdf(-E99,50,60,7.14) normalcdf(-E99,50,400,7.14)
@perl
Are you familiar with binomial probability distributions?
not really!
first find the mean and st. dev for a binomial distribution mean = n*p st. dev = sqrt( np (1-p))
well you'll start there and then use a normal distribution to approximate it. What's odd is that they didn't account for the continuity correction factor. Oh well Anyways, we are given n = 400 trials p = 0.15 is the probability of success q = 1-p = 1-0.15 = 0.85 is the probability of failure use these values to compute the mean mu and standard deviation sigma mu = n*p = 400*0.15 = 60 sigma = sqrt(n*p*q) = sqrt(400*0.15*0.85) = 7.14
wow thanks guys, now I can do the rest of these problems now that i have an example!
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