Question

Is the answer B? I have to simplify. PICTURE BELOW WILL MEDAL :)

Answer 1

yes it is B

Answer 2

wait can you stay for more?

Answer 3

depends on the question...if it's easy... no problem

Answer 4

this is kinda tricky I think its A or B im not sure

Answer 5

well we need the exponent laws for \[\frac{a^m}{a^n} \rightarrow a^{m-n}\] take it one at a time. for example if we have a = y, m = 5 and n = 3, we have \[\frac{y^5}{y^3} \rightarrow y^{5-3}\]

Answer 6

what is 5-3?

Answer 7

2

Answer 8

yes so you have \[y^2 \]. Now do the same thing for the z exponent

Answer 9

z6

Answer 10

Z^6

Answer 11

yes so your answer is \[y^2z^6\]

Answer 12

why isn't a fraction?

Answer 13

why isnt it a fraction*

Answer 14

we have positive exponents, so there's no denominator... if you have a negative exponent like \[a^{-n} \rightarrow \frac{1}{a^n}\] then we need to rewrite it. Negative exponents are usually not allowed.

Answer 15

thats how the next one looks hold up Im going to post it

Answer 16

ok..
A negative exponent just means that the base is on the wrong side of the fraction line, so you need to flip the base to the other side.

Answer 17

I just use the elevator rule.. whenever the negative exponent is on the numerator it goes down to the denominator... when there is a negative exponent on the denominator it goes up to the numerator.

Answer 18

my teacher said there shouldnt be any negative exponent in my final answer

Answer 19

\[\frac{a^m}{a^n} \rightarrow a^{m-n}\] only this time we have a y = x, m = -5, and n = 9

so we have

\[\frac{x^{-5}}{x^9} \rightarrow x^{-5-9}\]

so what is -5-9 ?

Answer 20

-14

Answer 21

yes but due to the fact that negative exponents aren't allowed we need to rewrite is as
\[\frac{1}{x^{14}}\]

We define a number with a negative exponent
\[a^{-n} = \frac{1}{a^n}\]

It is the reciprocal of that number with a positive exponent

The \[a^{-n}\] is the reciprocal of \[a^n \]

Answer 22

I'm going to post the last 4, im going to answer the next one tell me if im wrong

Answer 23

is it A?

Answer 24

no

Answer 25

its B

Answer 26

\[\frac{a^m}{a^n} \rightarrow a^{m-n} \] (exponent law)

a = b, m =-2 n = -6.

what's -2-6 ?

Answer 27

wait hold on.. I messed up . x.x

Answer 28

-2-(-6)

Answer 29

4 lol

Answer 30

first one was right sorry sorry ^^

Answer 31

oh I got it right?

Answer 32

its A?

Answer 33

yeah because I neglected something

Answer 34

heres where it gets harder 2 more after this one by the way

Answer 35

weeeeee distributing exponents...

Answer 36

it's either write the whole fraction 7 times and add the exponents one by one or just distribute the exponent on x and y which is must faster

Answer 37

so its D?

Answer 38

it's like we have x or x to the first power... \[(x^1)^7 \rightarrow (x^{(1)(7)})\] yes it is

Answer 39

it is D or no?

Answer 40

it's D

Answer 41

okay 1 more after this one :)

Answer 42

is it B?

Answer 43

no.. because you are distributing the 5
distribution is multiplication . the 3 and the z portion is right for B but not x

Answer 44

so its A because of 2 times 5?

Answer 45

??

Answer 46

oh yeah... sorry I was trying to prove something to another user... it is A because you are distributing the exponent 5 all over the entire problem so you should have 3^5 x^(2)(5)/z^5

Answer 47

and 2 x 5 = 10

Answer 48

heres the last one

Answer 49

I'll give a hint: all of them switch places thanks to the distribution of the negative. whatever is on the numerator goes to the denominator and whatever is on the denominator goes on the numerator.

Answer 50

D?

Answer 51

no... the -4 wasn't distributed on the 3 and when you have a problem like this you need to distribute everything.. all the numbers and variables have that distribution .

Answer 52

okay

Answer 53

C?

Answer 54

yes

Answer 55

thank you so so much, are you going to be online still in like 8min?

Answer 56

because of the -4 which is already a negative exponent 3^(-4)x^(-4) goes down and y^(-4) goes up

Answer 57

I think I should still be there... on os

Answer 58

theres another math homework I need help with so ill get back to you in a bit :) thank you by the way

Answer 59

ok :)