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Mathematics 7 Online
OpenStudy (anonymous):

What is the slope of the line shown in the graph? −2 −1 −1 over 2 1 over 2

OpenStudy (anonymous):

pooja195 (pooja195):

\[\huge~Slope=\frac{ Rise }{ Run}\]

OpenStudy (anonymous):

never seen that before ha so would it be a ?

pooja195 (pooja195):

ooo wait

OpenStudy (sohailiftikhar):

1 over 2

OpenStudy (anonymous):

Thats wrong lol

pooja195 (pooja195):

-2 i think is right...

OpenStudy (anonymous):

yea because i dont see any of the other answers being any lose to right tbh compared to -2

OpenStudy (anonymous):

Guys it's C.

OpenStudy (anonymous):

explain ?

pooja195 (pooja195):

We are moving to the left (run)

OpenStudy (anonymous):

Like pooja said rise over run

pooja195 (pooja195):

run is -2 .-.

pooja195 (pooja195):

and we only went up 1

pooja195 (pooja195):

when you divde you get -2 .-.

OpenStudy (sohailiftikhar):

oh sorry its C... as slope is in second quad.. so it will be negative..

pooja195 (pooja195):

.-.

OpenStudy (anonymous):

im confused lol

OpenStudy (anonymous):

haha -2 was wrong

pooja195 (pooja195):

Did it show y?

OpenStudy (anonymous):

no its just one of thise test that tells you that u got it wrong lol XP

pooja195 (pooja195):

test?

OpenStudy (anonymous):

i am taking a practice test yeah review

pooja195 (pooja195):

thats interesting.

OpenStudy (sohailiftikhar):

so what is the correct ans ..?

OpenStudy (anonymous):

im guessing -1/2 but it doesnt say

OpenStudy (anonymous):

because all the other answers are even more foolish >.>

OpenStudy (anonymous):

thanks for your guy's help either way i appreciate the effort lol

OpenStudy (sleepyjess):

The slope of a line is \(\dfrac {y_2-y_1}{x_2-x_1}\)

OpenStudy (sleepyjess):

(-2, 2) is \((x_1, y_1)\) (0,1) is \((x_2, y_2)\)

OpenStudy (sleepyjess):

Now we just plug in the values into the formula

OpenStudy (sohailiftikhar):

yes it is ...

OpenStudy (anonymous):

thank you for that im gonna write that down !!!!!!!!!!

OpenStudy (sleepyjess):

No problem! Would you still like to find the answer on this?

OpenStudy (sleepyjess):

x1, y1 is always going to be the point on the left, and x2, y2 is always going to be the point on the right

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