Mathematics
7 Online
OpenStudy (anonymous):
What is the slope of the line shown in the graph?
−2
−1
−1 over 2
1 over 2
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OpenStudy (anonymous):
pooja195 (pooja195):
\[\huge~Slope=\frac{ Rise }{ Run}\]
OpenStudy (anonymous):
never seen that before ha so would it be a ?
pooja195 (pooja195):
ooo wait
OpenStudy (sohailiftikhar):
1 over 2
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OpenStudy (anonymous):
Thats wrong lol
pooja195 (pooja195):
-2 i think is right...
OpenStudy (anonymous):
yea because i dont see any of the other answers being any lose to right tbh compared to -2
OpenStudy (anonymous):
Guys it's C.
OpenStudy (anonymous):
explain ?
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pooja195 (pooja195):
We are moving to the left (run)
OpenStudy (anonymous):
Like pooja said rise over run
pooja195 (pooja195):
run is -2 .-.
pooja195 (pooja195):
and we only went up 1
pooja195 (pooja195):
when you divde you get -2 .-.
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OpenStudy (sohailiftikhar):
oh sorry its C...
as slope is in second quad.. so it will be negative..
pooja195 (pooja195):
.-.
OpenStudy (anonymous):
im confused lol
OpenStudy (anonymous):
haha -2 was wrong
pooja195 (pooja195):
Did it show y?
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OpenStudy (anonymous):
no its just one of thise test that tells you that u got it wrong lol XP
pooja195 (pooja195):
test?
OpenStudy (anonymous):
i am taking a practice test yeah review
pooja195 (pooja195):
thats interesting.
OpenStudy (sohailiftikhar):
so what is the correct ans ..?
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OpenStudy (anonymous):
im guessing -1/2 but it doesnt say
OpenStudy (anonymous):
because all the other answers are even more foolish >.>
OpenStudy (anonymous):
thanks for your guy's help either way i appreciate the effort lol
OpenStudy (sleepyjess):
The slope of a line is \(\dfrac {y_2-y_1}{x_2-x_1}\)
OpenStudy (sleepyjess):
(-2, 2) is \((x_1, y_1)\)
(0,1) is \((x_2, y_2)\)
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OpenStudy (sleepyjess):
Now we just plug in the values into the formula
OpenStudy (sohailiftikhar):
yes it is ...
OpenStudy (anonymous):
thank you for that im gonna write that down !!!!!!!!!!
OpenStudy (sleepyjess):
No problem! Would you still like to find the answer on this?
OpenStudy (sleepyjess):
x1, y1 is always going to be the point on the left, and x2, y2 is always going to be the point on the right