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Mathematics 13 Online
OpenStudy (anonymous):

Prove that the two circles shown below are similar

OpenStudy (anonymous):

@is3535

imqwerty (imqwerty):

cookie error comes when i open the link

OpenStudy (anonymous):

SAME WITH ME.

OpenStudy (anonymous):

humm okay one sec let me screen shot the image and post it :p

OpenStudy (is3535):

me to

OpenStudy (anonymous):

OpenStudy (anonymous):

there u go let me know if that works

imqwerty (imqwerty):

yes it works

OpenStudy (is3535):

no ther no simliar B is 5 and D 7 i say

OpenStudy (anonymous):

okay can yall help me? this is what i have so far.. idk if its right All circles are similar because you can scale one circle to be the same size as another (bigger or smaller) circle. They effectively have the same shape.

OpenStudy (is3535):

im not 1000 % that i said

OpenStudy (anonymous):

humm... i dont think that is right haha

OpenStudy (anonymous):

you can go from one figure to the other with a translation and a dilation, does that make them similar? im not so sure...

OpenStudy (anonymous):

what if i say this?? Theorem: Any two circles are similar. Proof: Given a circle of radius r and a second circle of radius R , perform a translation so that their centers coincide. A dilation from the common center of the circles with scale factor R takes the points of one circle and maps them onto the second. Thus we have mapped one circle onto the other via a translation and a dilation. The circles are simila

OpenStudy (anonymous):

First circle with center (-1,5) and radius=4 second circle with center (7,4) and radius =2

OpenStudy (anonymous):

@CayleeS23 ... where did you get that theorem from?

OpenStudy (anonymous):

Their similar because

OpenStudy (anonymous):

hello???

OpenStudy (anonymous):

looks like they are similar, and the proof would be what @CayleeS23 posted before...

OpenStudy (anonymous):

im confused...

OpenStudy (anonymous):

listen

OpenStudy (anonymous):

very simple

OpenStudy (anonymous):

their both round and they both have no sides

OpenStudy (anonymous):

proved

OpenStudy (anonymous):

feel free to fan and medal me

OpenStudy (anonymous):

no that doesnt prove anything haha get otta here dude...

OpenStudy (anonymous):

i guess a better proof would be taking the ratio of their perimeter to their radius for each of them, you will get the same in both cases, actually you get: \[2\pi\] for any circle so they are similar

OpenStudy (anonymous):

I tried. I failed/

OpenStudy (anonymous):

hey sometimes the answer is easier than you think

OpenStudy (anonymous):

ohh okay that makes since so should i just put that?? proof would be taking the ratio of their perimeter to their radius for each of them, you will get the same in both cases, actually you get: 2π for any circle so they are similar

OpenStudy (anonymous):

can u show me how u did that math? to prove that they are both 2pi

OpenStudy (anonymous):

this is pi|dw:1433531216624:dw|

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