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Mathematics 8 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

Solve 3 over x minus 3 equals the quantity of x over x minus 3, minus three-halves for x and determine if the solution is extraneous or not. x = 3, non-extraneous x = 3, extraneous x = -3, extraneous x = -3, non-extraneous

OpenStudy (anonymous):

\[\frac{ 3 }{ x - 3 } = \frac{ x }{ x -3 } - \frac{ 3 }{ 2 }\] @Nnesha @timo86m

OpenStudy (anonymous):

@jigglypuff314

jigglypuff314 (jigglypuff314):

multiply both sides by 2(x-3)

jigglypuff314 (jigglypuff314):

I suppose that should give you something like 2*(3) = 2*(x) - 3(x-3) can you solve for x from there? :)

OpenStudy (anonymous):

is x 3?

jigglypuff314 (jigglypuff314):

that's what I got! :D

jigglypuff314 (jigglypuff314):

oh wait now we have to see if it is extraneous or non

jigglypuff314 (jigglypuff314):

try plugging it back into the original stufff if there's problems with it -> extraneous if it comes out to be true (like 3=3) then -> non extraneous

OpenStudy (anonymous):

give me a sec

OpenStudy (anonymous):

wait sorry it wasn't loading bc of the wifi but its extraneous

jigglypuff314 (jigglypuff314):

yup! ^_^

OpenStudy (anonymous):

thnx

OpenStudy (anonymous):

can you help me with a couple more?

OpenStudy (anonymous):

Given the function f(x) = The quantity of 5x minus 3, divided by 4, which of the below expressions is correct? f−1(x) = The quantity of 3 minus 5x, divided by 4 f−1(x) = The quantity of 4x plus 3, divided by 5 f−1(x) = The quantity of 4x minus 3, divided by 5. f−1(x) = The quantity of negative 5x minus 3, divided by 4.

OpenStudy (anonymous):

\[f(x)= \frac{ 5x - 3 }{ 4 }\]

jigglypuff314 (jigglypuff314):

to get the inverse of a function, you flop the x and y and solve for the new y \[x = \frac{ 5y - 3 }{ 4 }\]now try to get y alone ^_^

OpenStudy (anonymous):

so \[x +3 = \frac{ 5y }{ 4 }\]

OpenStudy (anonymous):

\[f ^{-1}(x) = \frac{ 4x + 3 }{ 5 }\]

OpenStudy (anonymous):

am i right>?

jigglypuff314 (jigglypuff314):

correct!

OpenStudy (anonymous):

thnx i have more can you help?

jigglypuff314 (jigglypuff314):

sure, although I might take a little time to answer (multi tasking atm) ^_^

OpenStudy (anonymous):

Below are two different functions, f(x) and g(x). What can be determined about their slopes? f(x)= −1x + 1 The function g of x going through 0, 3 and 2, negative 1 The function f(x) has a larger slope. The function g(x) has a larger slope. They both have the same slope. The relationship between slopes cannot be determined.

OpenStudy (anonymous):

np thnx

jigglypuff314 (jigglypuff314):

ew the wording of this is weird do they mean larger as in slope of -2 is greater than slope of -1 because it is steeper? or do they mean larger as in -1 is greater than -2 because it is?

OpenStudy (anonymous):

tbh idk

jigglypuff314 (jigglypuff314):

I suggest you open another question to ask this someone else deciphering this weirdly phrased english confuses me every time and I would feel bad if I gave you a wrong answer :3

OpenStudy (anonymous):

okay ill skip that one for now

OpenStudy (anonymous):

Which of the following represents \[3x ^{5/7}\] in radical form? 3 times seventh root of x to the fifth power seventh root of 3 x to the fifth power 3 times fifth root of x to the seventh power fifth root of 3 x to the seventh power

OpenStudy (anonymous):

i think its B

jigglypuff314 (jigglypuff314):

B? but B has 3 inside the root, why would we want that? x^(5/7) = seventh root of x to the fifth power

OpenStudy (anonymous):

so A

jigglypuff314 (jigglypuff314):

yessss :)

OpenStudy (anonymous):

thnx

OpenStudy (anonymous):

To which graph does the point (2, 4) belong? y ≥ x + 3 y ≥ −x + 8 y ≥ 4x − 5 y ≥ −2x + 9

OpenStudy (anonymous):

i think its C

jigglypuff314 (jigglypuff314):

That's right! Good Job!

OpenStudy (anonymous):

thnx

OpenStudy (anonymous):

A function is created to represent the miles per gallon your car gets. What restrictions would be made to the domain? The domain would only include integers. The domain would only include positive integers. The domain would include all real numbers. The domain would only include positive numbers.

OpenStudy (anonymous):

D? but not sure...

jigglypuff314 (jigglypuff314):

I believe that would be the best answer ^_^ You're doing great!

OpenStudy (anonymous):

thnx

OpenStudy (anonymous):

The graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k: a parabola with a vertex of negative 5, negative 2 What is the value of h? 2 −5 −2 5

jigglypuff314 (jigglypuff314):

vertex = (h, k)

OpenStudy (anonymous):

OpenStudy (anonymous):

this one idk the answer to this one

jigglypuff314 (jigglypuff314):

well if the vertex = (h , k) and they told you that vertex = (-5, -2)

OpenStudy (anonymous):

oh okay give me a sec then

OpenStudy (anonymous):

so -5

jigglypuff314 (jigglypuff314):

yep! :)

OpenStudy (anonymous):

thnx

OpenStudy (anonymous):

Use the table of the function f(x) = x4 - 4x to answer this question: x f(x) -2 24 -1 5 0 0 1 -3 2 8 What is the average rate of change from x = -1 to x = 2? -3 -1 1 3

OpenStudy (anonymous):

D

jigglypuff314 (jigglypuff314):

"average rate of change" is just their complicated way of saying "find the slope" between (-1, 5) and (2, 8)

OpenStudy (anonymous):

3/3 = 1

OpenStudy (anonymous):

so 1

jigglypuff314 (jigglypuff314):

yep ^_^

OpenStudy (anonymous):

o h ok thnx i would have go thtat one wrong

OpenStudy (anonymous):

The function for the cost of materials to make a shirt is f(x) = 5/6x + 5, where x is the number of shirts. The function for the selling price of those shirts is g(f(x)), where g(x) = 5x + 6. Find the selling price of 18 shirts. 106 120 185 196

jigglypuff314 (jigglypuff314):

5((5/6)*(18) +5) + 6

OpenStudy (anonymous):

still trying to solve this so idk the answer yet

OpenStudy (anonymous):

i got A

jigglypuff314 (jigglypuff314):

g(f(x)) = 5((5/6x + 5) + 6 and yes, that's what I got too

OpenStudy (anonymous):

yay!

OpenStudy (anonymous):

George and Bella are asked to solve −3x − 30 = 5x + 18. Identify where one of them made an error. George − 3x − 30 = 5x + 18 − 3x − 30 − 5x = 5x + 18 −5x −8x − 30 = 18 − 8x − 30 + 30 = 18 + 30 −8x = 48 Negative 8x over negative 8 equals 48 over negative 8 Bella x = − 6 − 3x − 30 = 5x + 18 −3x − 30 − 3x = 5x + 18 − 3x − 30 = 2x + 18 −30 − 18 = 2x + 18 −18 − 48= 2x Negative 48 over 2 equals 2x over 2 x=−24 Bella made the error when she subtracted 18 Bella made the error when she subtracted 3x George made the error when he subtracted 5x George made the error when he divided by −8

OpenStudy (anonymous):

i think the answe is B

jigglypuff314 (jigglypuff314):

that's right! :D

OpenStudy (anonymous):

yay

OpenStudy (anonymous):

What is the simplified form of the quantity x squared plus 5x plus 6 over 15 x y squared all over the quantity 2x squared plus 7x plus 3 over 5 x squared y ? 3y times the quantity 2x plus 1 over x times the quantity x plus 2 x times the quantity x plus 2 over 3y times the quantity 2x plus 1 x times the quantity x minus 2 over 3y times the quantity 2x minus 1 3y times the quantity 2x minus 1 over x times the quantity x minus 2

OpenStudy (anonymous):

\[\frac{ \frac{ x^2 + 5x + 6 }{ 15xy^2 } }{ \frac{ 2x^2 + 7x + 3 }{ 5x^2y } }\]

OpenStudy (anonymous):

in case you think the one above is too small to read

jigglypuff314 (jigglypuff314):

good! now the big fraction line can be interpreted as a division sign and dividing is just multiplying by the flipped so x^2 + 5x +6 5 x^2 y ----------- * -------------- 15 x y^2 2x^2 + 7x + 3

jigglypuff314 (jigglypuff314):

you can factor x^2 + 5x + 6 as well as 2x^2 + 7x + 3

OpenStudy (anonymous):

yeah will is be (x + 3) (x + 2) and (x + 3) (2x + 1) and since we have both of (X + 3) would it be \[\frac{ x + 2 }{ 15xy^2 } \times \frac{ 5x^2y }{ 2x +1 }\]

jigglypuff314 (jigglypuff314):

great! then try canceling stuff in the 5 x^2 y / 15 x y^2 :)

OpenStudy (anonymous):

would it be \[\frac{ x + 2 }{ 3y } \times \frac{ x }{ 2x + 1 }\]

OpenStudy (anonymous):

not sure though ...

jigglypuff314 (jigglypuff314):

it is!

OpenStudy (anonymous):

yay so would it make it \[\frac{ x(x+2) }{ 3y(2x +1) }\]

jigglypuff314 (jigglypuff314):

mhmmm ^_^

OpenStudy (anonymous):

yay im so happy im actually learning this!

OpenStudy (anonymous):

one more for now

OpenStudy (anonymous):

Use the graph below for this question: graph of parabola going through negative 1, 7 and negative 3, 9. What is the average rate of change from x = −1 to x = −3? 5 −3 1 −1

OpenStudy (anonymous):

tbh idk this one

jigglypuff314 (jigglypuff314):

slope between the points (-1, 7) and (-3, 9) basically :P

OpenStudy (anonymous):

so -2/2 -1?

OpenStudy (anonymous):

-1

jigglypuff314 (jigglypuff314):

I think so ^_^

OpenStudy (anonymous):

okay well thank you so much! thats it for now then i got to do more homework in like 30 minutes but im gonna post the one that you didn't know the answer to and then take a break THANK YOU!!

jigglypuff314 (jigglypuff314):

glad I could help ^_^ hopefully someone will be able to help you with that one :3 I'm going to sleep, good night :)

OpenStudy (anonymous):

good night!

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