Solve the equation by completing the square. 6x^2-x-5=0 So far i got x^2-1/6x-5/6=0 x^2-1/6x=5/6 Now i dont understand this step by add the square of half of -1/6 to both sides I dont understand what that means please help
why?....
Cant we just factor it?
okay
@Tyler1204 ?
@pooja195 i have the steps and it says add the square of half of -1/6 to both sides but i dont understand how that answer is 1/144
hmm im not sure how to do it that way @Loser66 might know :3
you are good until \(x^2 -(1/6)x -(5/6)=0\) Now, I pick the middle term to say, ok? to have a complete the square, you have formula \((x-a)^2 = x^2 -2ax+a^2\) right? your middle term is (1/6) x, right?
so, to find a, the term we need to have the complete square, I do \(2a x = \dfrac{1}{6}x\), hence \(2a=\dfrac{1}{6}\), so \(a =\dfrac{1}{12}\) so far so good?
erm erm @Loser66 ok like what you saying sounds good lol but like i have to follow this way :S did you see the picture i posted ? http://prntscr.com/7dnq4a
Now, the original one \(x^2 -2 (\dfrac{1}{12}) x +\color{red}{(\dfrac{1}{12})^2} - \color{red}{(\dfrac{1}{12})^2}-\dfrac{5}{6}=0\)
@Tyler1204 it is not "sounds good". I explained you why 1/144 appears.
OH OH erm ok let me re read then lol sorry
You killed my feeling.
Grrr im still confused because for me it dos not say anything about that formula you said :/ (x-a)^2=x^2-2ax+a^2 Did you open the picture? because like i have to follow what it says :S
@Loser66
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