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Mathematics 7 Online
OpenStudy (anonymous):

How do you find the complex roots of a polynomial?

OpenStudy (anonymous):

Do you have an example? The process could be different depending on what you have.

OpenStudy (anonymous):

4x^3 – 12x + 9 = 0 Something like this... The example my teacher gave to me said that because equation has a degree of 3 it has 3 complex roots... and i think im interpreting that wrong

OpenStudy (anonymous):

Its impossible to have 3 complex roots. There can only be an even number of roots.

OpenStudy (anonymous):

even number of complex I mean

OpenStudy (anonymous):

he said that for imaginary roots

OpenStudy (anonymous):

Yeah, complex roots and imaginary roots you can consider to be the same thing. There must be an even number of imaginary roots. So this cubic either has 2 imaginary roots or 0.

OpenStudy (anonymous):

okay so it can be either one? or do i have to find out which one?

OpenStudy (anonymous):

Yes, you might have 2 imaginary or you might have 0 imaginary. You would want to ty and see if you could factor the cubic and find its zeros first.

OpenStudy (anonymous):

Okay! Thanks for clearing that up for me!

OpenStudy (anonymous):

Mhm, sure. If you had to actually do this problem, though, it appears that it wont factor cleanly. The best you could do is show that it does have 1 real zero and that there cant be another real zero. So yeah, this problem has 2 imaginary roots.

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

No problem

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