Question

In a series circuit with 9V battery and two resistors, one 100 Ohms and one at 350 Ohms, this is the voltage across each one respectively.

**What is that voltage?

Answer 1

the current in your circuit is:
\[\Large I = \frac{{\Delta V}}{{{R_1} + {R_2}}} = \frac{9}{{100 + 350}}\]
since your resistors are connected in series, and the equivalent resistance is:
R_1+R_2

Answer 2

ok! and solving we get 0.02?

Answer 3

correct!

Answer 4

is that the voltage across each one? :/ 0.02 is our solution?

Answer 5

now using the Ohm's law, we can compute the requested voltage drop as below:

\[\Large \begin{gathered}
\Delta {V_1} = I \times {R_1} = 0.02 \times 100 \hfill \\
\Delta {V_2} = I \times {R_2} = 0.02 \times 350 \hfill \\
\end{gathered} \]