The prism has a surface area of 202 ft2. What would the surface area of the prism be if each dimension were tripled?
the new dimensions are: 5*3=... 9*3=... 4*3=...
15 27 and 12
correct!
then x by them?
which us 4860
please wait a moment, I'm checking your computation
kk
your problem asks for the area of the total surface of the prism. Now the area of the total surface of your prism is given by the subsequent computation: A=2*(15*27+ 15*12+27*12)=...
i got 121608
is that correct?
here more steps: \[\Large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = ... \hfill \\ \end{gathered} \]
1314
I got a different result
wait do we add the two together?
yes!
i got 122922
you have to compute this: 405+180+324=... \[\large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = \hfill \\ \hfill \\ = 2 \times 909 = ... \hfill \\ \end{gathered} \]
1818 plus 122922 = 124740
no, it is: A= 1818 feet^2 only
-3- hm?
I didnt get that, sorry. :/
the new area of the total surface is, namely your answer, is: \[\Large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = \hfill \\ \hfill \\ = 2 \times 909 = 1818fee{t^2} \hfill \\ \end{gathered} \]
oh :l
i see now...
since we have to sum the area of all of the six sides of your prism
so 10908? 1818 x 6
no, we have finished, your answer is: A= 1818 feet^2
oh kk. Thank you!!! ^u^
:)
Old Surface Area = 202 ft^2 New Surface Area = 1818 ft^2 Notice we have this ratio: (new area)/(old area) = 1818/202 = 9 and how 3^2 = 9. This is no coincidence. The old surface area is multiplied by 3^2 = 9 to get the new surface area. If you asked "What would the surface area of the prism be if each dimension were quadrupled?", then you would multiply the old surface area by 4^2 = 16 to get the new surface area
Join our real-time social learning platform and learn together with your friends!