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Mathematics 11 Online
OpenStudy (gabbyalicorn):

The prism has a surface area of 202 ft2. What would the surface area of the prism be if each dimension were tripled?

OpenStudy (gabbyalicorn):

OpenStudy (michele_laino):

the new dimensions are: 5*3=... 9*3=... 4*3=...

OpenStudy (gabbyalicorn):

15 27 and 12

OpenStudy (michele_laino):

correct!

OpenStudy (gabbyalicorn):

then x by them?

OpenStudy (gabbyalicorn):

which us 4860

OpenStudy (michele_laino):

please wait a moment, I'm checking your computation

OpenStudy (gabbyalicorn):

kk

OpenStudy (michele_laino):

your problem asks for the area of the total surface of the prism. Now the area of the total surface of your prism is given by the subsequent computation: A=2*(15*27+ 15*12+27*12)=...

OpenStudy (gabbyalicorn):

i got 121608

OpenStudy (gabbyalicorn):

is that correct?

OpenStudy (michele_laino):

here more steps: \[\Large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = ... \hfill \\ \end{gathered} \]

OpenStudy (gabbyalicorn):

1314

OpenStudy (michele_laino):

I got a different result

OpenStudy (gabbyalicorn):

wait do we add the two together?

OpenStudy (michele_laino):

yes!

OpenStudy (gabbyalicorn):

i got 122922

OpenStudy (michele_laino):

you have to compute this: 405+180+324=... \[\large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = \hfill \\ \hfill \\ = 2 \times 909 = ... \hfill \\ \end{gathered} \]

OpenStudy (gabbyalicorn):

1818 plus 122922 = 124740

OpenStudy (michele_laino):

no, it is: A= 1818 feet^2 only

OpenStudy (gabbyalicorn):

-3- hm?

OpenStudy (gabbyalicorn):

I didnt get that, sorry. :/

OpenStudy (michele_laino):

the new area of the total surface is, namely your answer, is: \[\Large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = \hfill \\ \hfill \\ = 2 \times 909 = 1818fee{t^2} \hfill \\ \end{gathered} \]

OpenStudy (gabbyalicorn):

oh :l

OpenStudy (gabbyalicorn):

i see now...

OpenStudy (michele_laino):

since we have to sum the area of all of the six sides of your prism

OpenStudy (gabbyalicorn):

so 10908? 1818 x 6

OpenStudy (michele_laino):

no, we have finished, your answer is: A= 1818 feet^2

OpenStudy (gabbyalicorn):

oh kk. Thank you!!! ^u^

OpenStudy (michele_laino):

:)

jimthompson5910 (jim_thompson5910):

Old Surface Area = 202 ft^2 New Surface Area = 1818 ft^2 Notice we have this ratio: (new area)/(old area) = 1818/202 = 9 and how 3^2 = 9. This is no coincidence. The old surface area is multiplied by 3^2 = 9 to get the new surface area. If you asked "What would the surface area of the prism be if each dimension were quadrupled?", then you would multiply the old surface area by 4^2 = 16 to get the new surface area

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