Question

Solve x2- 5x + 6 = 0 using the quadratic formula.

Answer 1

List your abc values

Answer 2

\[\huge\rm \frac{ - b \pm \sqrt{b^2 -4ac} }{ 2a }\]
quadratic formula
where abc values are \[\huge\rm Ax^2 +Bx+C=0\]

Answer 3

?

Answer 4

Imagine your equation is in the form Ax^2+Bx+C=0. What is your A, B, and C?

Answer 5

What are the A B C values

Answer 6

Also sometimes you would have to manipulate your equation to get it in that form but in this case it's set up nicely for you

Answer 7

a=1
b=5
and
c=6

Answer 8

hmm
a=1
b= -5
c=6

Answer 9

cant i do x^2 +2x + 3x -5?

Answer 10

LEts stick to this its less complicated

Answer 11

\[\huge~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \]

Answer 12

fimiliar with this?

Answer 13

x2- 5x + 6 = 0

x^2 - 2 + 3 + 6
(x^2-2x) (3x+6)
divide by x and 2
so....

Answer 14

yes

Answer 15

By factoring? Its asking to use the quadratic formula .

Answer 16

\[\huge~x=\frac{ -(-5) \pm \sqrt{(-5)^2-4(1)(6)} }{ 2(1) } \]

Answer 17

simplyfy this

Answer 18

So the x2 can be written as 2x because they are communitive terms. Since the 2x and 5x are like terms, they can combine so 2x-5x = -3x. Ok. Now, since u want to use quadratic u need to assign an a b and c value. The a value is the coefficient of an x^2 in a quadratic equation. Since u don't have a quadratic equation, the coefficient is 0. So the a value is zero. The b value is the -3 and the c value is the number without an x (I don't remember what it was.) Plug the a, b and c values into the quadratic equation and solve. I hope that helps, because i am not good at explaining things. If u still don't understand, I'm sure Kahn academy has a video on it

Answer 19

\[5\pm/2 \sqrt{-6}\]

Answer 20

Oh. I got all the numbers wrong...

Answer 21

Very sorry

Answer 22

\[\frac{ 5\pm \sqrt{1} }{ 2 }\]

Answer 23

simplfy

Answer 24

Set up 2 equations

Answer 25

\[5\pm 1/2\]

Answer 26

oh

Answer 27

The equation is 5+-(5^2 -4(1)(6))^1/2 /2(1). ^1/2 means square root

Answer 28

jpro, can u stop talking

Answer 29

thats what i have above xD
\[\frac{ 5+\sqrt{1} }{ 2}\]
\[\frac{ 5-\sqrt{1} }{ 2}\]
I did this because we have a plus and minus sign so we need 2 seperate equations

Answer 30

so + that and - that

Answer 31

yea :)

Answer 32

is that the answer?

Answer 33

x = 2 and x = 3
x = - 4 and x = - 3
x = 5 and x = - 3
x = - 2 and x = 4

Answer 34

3 and 2

Answer 35

yep :)

Answer 36

Thats right good job :)

Answer 37

i learned this along time ago the fist thing i learned, but what im doing now has nothing to with it...

Answer 38

lol what are you learning right now ?

Answer 39

things like x^2 +6=180

Answer 40

Oh so like factoring?

Answer 41

Let me know if you need any help :)

Answer 42

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Answer 43

not really
were r kinda using a diffent methon with squareroots

Answer 44

oh right thats what its called :)