help pls
@jim_thompson5910 @Compassionate @Kainui
where are you stuck?
i havent started @jim_thompson5910
so you're not sure what \(\Large \bar{x}\) means ?
im not sure how to do anything... this is a summer class i havent learned anything from this...this is a class to get a credit @jim_thompson5910
\[\Large \bar{x}\] means xbar, this is the sample mean
you add up all the numbers in the sample and then divide by the number of numbers
so you have to first go through the graph given to you and pull out all of the data values
Each one of the dots represents an amount of numbers in the set. So if a 60 had 2 dots on it, you would have 2 60's in the sequence. (60, 60, ... ) so continue doing that for all the numbers
is number 1 80? @jim_thompson5910
you're asking about the sample mean being 80? or something else?
im asking is number 1 80 or 191.47619 @jim_thompson5910
the mean isn't either of those values
well can u help @jim_thompson5910
did you get these values 60,61,63,65,68,68,68,69,69,70,70,72,74,76,76,76,78,79,80,80,80,80,82,82,82,82,84,85,85,86,86,86,87,88,89,90,90,90,90,90,92,92,92,92,95,95,95,98,99,100 ??
there are 50 numbers in that list above (each one pulled from each dot)
yes
80.42 @jim_thompson5910
when you added all of the 50 numbers up, what did you get?
4021 @jim_thompson5910
you made an error, it should be larger than 4021
4176 and when divided by 50 i got 83.52 @jim_thompson5910
4176 is too high
thats wat i keep getting @jim_thompson5910
60+61+63+65+68+68+68+69+69+70+70+72+74+76+76+76+78+79+80+80+80+80+82+82+82+82+84+85+85+86+86+86+87+88+89+90+90+90+90+90+92+92+92+92+95+95+95+98+99+100 = 4,086
so 81.72 @jim_thompson5910
yes that is xbar
ok wat about number 2 @jim_thompson5910
use something like this https://www.easycalculation.com/statistics/standard-deviation.php
type in all the numbers separated by commas
ok i did now wat am i looking for in number 2 @jim_thompson5910
do you see where it says Standard deviation 10.47259
yes @jim_thompson5910
thats the answer to 2
3 4 and 5 @jim_thompson5910 wat i do
xbar will be used in place of \(\Large \mu\) the standard deviation is \(\Large \sigma\)
what you need to do is compute 81.72 - k*10.47259 for k = 1, k = 2, and k = 3 also compute 81.72 + k*10.47259 for k = 1, k = 2, and k = 3
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