Question

Use the squared Identities to simplify 2cos^2 (x) * cos^2 (x)

Answer 1

@ganeshie8 @JackJordan

Answer 2

uhmm... how simple do you want it I mean an easy one would be just 2cos^4(x) lol

Answer 3

a) 1-cos(4x) / 4
b) 1+4cos(2x)+cos(4x) / 4
c) 1+cos(4x) / 4
d) 1+4cos(2x)-cos(4x) / 4

Answer 4

@ganeshie8

Answer 5

are you sure you haven't miswritten the second one?

Answer 6

b) 1+4cos(2x)+cos(4x) / 4

Answer 7

thats what i have

Answer 8

@ganeshie8

Answer 9

@JackJordan

Answer 10

@jim_thompson5910

Answer 11

someone help!

Answer 12

write both
\(\cos^2 x = \dfrac{1-\cos 2x}{2}\)

Answer 13

It must be a typo... I'm getting 1+4cos(2x)+cos(4x) + 3 / 4
sorry.

Answer 14

***\(\cos^2 x = \dfrac{1+\cos 2x}{2}\)

Answer 15

elementary mistake hartnn

Answer 16

and then expand it.

Answer 17

So my attempt leads to something similar to B but with +3 at the end. Either I'm wrong (not likely) or the question is wrong.

Answer 18

then using the same identity
you'll need to write
\(\Large \cos^2 2x = \dfrac{1+\cos 4x}{2}\)

Answer 19

ROOKIE MISTAKE!!!

Answer 20

sorry to everyone. I am so sorry

Answer 21

So I was right

Answer 22

so you got it now?

Answer 23

i must've made a huge typo

Answer 24

the question is
2sin^2 (x) cos^2x

Answer 25

sin. not cos. i can't believe i made that mistake.

Answer 26

okk,
then write
\(\large \sin^2 x = \dfrac{1-\cos 2x}{2}\)

thats the only difference

Answer 27

Dang it I knew you made that mistake!
Lol, it gives a difference of two squares at the top. I already did that.
The answer is a. Can you see why?

Answer 28

I'd like to see sbsbrand's attempt! :)

Answer 29

yay it worked! thanks everyone that stayed to help me even tho i wrote the question wrong.......XD