Question

QUICK QUESTION need someone who knows statistics

Answer 1

What's the problem here? @Michele_Laino answered your question just fine the first time around.

Answer 2

I didn't understand the equation.

Answer 3

someone help please

Answer 4

The \(\chi^2\) statistic is given as
\[\sum_{i=1}^n\frac{(\text{observed}_i-\text{expected}_i)^2}{\text{expected}_i}\]
where \(i\) denotes the category, which in this case is milkshake flavor. There are 3 of these, so \(n=3\).

\(\text{observed}_i\) is the recorded value of a given flavor, whereas \(\text{expected}_i\) is the expected value of a given flavor. For example, the parlor finds that \(202\) vanilla milkshakes were ordered, while they expected \(175\) to be ordered. So, the contribution of vanilla shakes to the \(\chi^2\) statistic is
\[\frac{(\text{observed}_\text{vanilla}-\text{expected}_\text{vanilla})^2}{\text{expected}_\text{vanilla}}=\frac{(202-175)^2}{175}\]
You do the same for the other flavors and add them together.
\[\chi^2=\frac{{{{\left( {202 - 175} \right)}^2}}}{{175}} + \frac{{{{\left( {112 - 125} \right)}^2}}}{{125}} + \frac{{{{\left( {269 - 250} \right)}^2}}}{{250}} \]

Answer 5

so from this you get "yes, the x^2 value was too high"?

Answer 6

@SithsAndGiggles

Answer 7

Well that depends on what value of \(\chi^2\) you get \(\chi^2\approx 6.96\). Since \(n=3\), you have \(n-1=2\) degrees of freedom. What \(p\) value do you get for a significance level of \(0.05\) and \(2\) degrees of freedom?

Answer 8

statistics is super not my thing. i hardly understand what you're talking about

Answer 9

@SithsAndGiggles

Answer 10

You'll have to be more precise. What do you not understand? I'll try my best to explain.

Answer 11

i dont understand any of this. is like a foreign language.

Answer 12

@sithsandgiggles

Answer 13

i just need the answer right now @sithsandgiggles

Answer 14

Thanks!! :) @SithsAndGiggles