Question

find

Answer 1

\(\large \color{black}{\begin{align}
&\text{if}\quad -3\leq x\leq 5 ,\quad x\in \mathbb{R} \hspace{.33em}\\~\\
&\text{find a and b such that } \hspace{.33em}\\~\\
&a\leq x^2 \leq b
\end{align}}\)

Answer 2

b is not 5

Answer 3

hmm

Answer 4

SOrry, 25, my bad

Answer 5

i'm thinking of taking root as a first option

Answer 6

Well, the minimum value of x^2 would be 0, which is fine since -3 <=x<=5. And the highest absolute value for -3<=x<=5 is 5, so then you would consider the maximum value of x^2 to be 25. So a = 0, b = 25.

Answer 7

I agree with @Concentrationalizing that little trick you had there was subtle but clever ^^

Answer 8

yes

Answer 9

the graph of \(y=x^2\) in the interval \([-3, 5]\)

Answer 10

ok thnx

Answer 11

what about this


\(\large \color{black}{\begin{align}
&\text{if}\quad 4\leq x^2\leq 25 ,\quad x\in \mathbb{R} \hspace{.33em}\\~\\
&\text{find a and b such that } \hspace{.33em}\\~\\
&a\leq x \leq b
\end{align}}\)