Mathematics
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OpenStudy (anonymous):
Given the functions f(x) = 3x + 2 −4/x
and g(x) = 2 − 3x, find the indicated values.
a) f(a + b)
b) g(a) − g(a − b) + f(a)
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OpenStudy (anonymous):
replace x in the equation above with (a+b)
OpenStudy (anonymous):
f(a+b)=3(a+b)+2 -4/(a+b)
OpenStudy (xapproachesinfinity):
wherever you x replace by a+b
\[f(x)=3x+2-\frac{4}{x}\]
\[f(\color {red}{a+b})=3(\color{red}{a+b})+2-\frac{4}{\color{red}{a+b}}\]
OpenStudy (xapproachesinfinity):
if for example f(x)=x^-2
they ask f(c)
\[f(\color{blue}{c})=\color{blue}{c}^2-2\]
just a matter of replacing the dummy variable
OpenStudy (anonymous):
whats a+b tho
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OpenStudy (anonymous):
what do i do when i set it up like that
OpenStudy (xapproachesinfinity):
that's what they asked you the evaluate
a+b standards as some variable
OpenStudy (xapproachesinfinity):
hmm you can simply more if they ask you
just depends on the question
OpenStudy (xapproachesinfinity):
in this case i would just leave it that way
OpenStudy (anonymous):
what about the second one?
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OpenStudy (xapproachesinfinity):
second you gonna do each one separately
g(a)
g(a-b)
f(a)
after that the results do
g(a)-g(a-b)+f(a)
OpenStudy (xapproachesinfinity):
let me see if you can do g(a)
OpenStudy (anonymous):
i thought were supposed to use the equation they gave us tho
OpenStudy (anonymous):
i dont know
OpenStudy (xapproachesinfinity):
what equation?
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OpenStudy (anonymous):
the second part
OpenStudy (xapproachesinfinity):
you have g(x) right
find g(a) by replacing x with a
OpenStudy (xapproachesinfinity):
i broke it down to steps as you can see
first find g(a)
then g(a-b)
then f(a) all separately
OpenStudy (xapproachesinfinity):
try to do g(a) first
let me see you do it
OpenStudy (anonymous):
so 2-3(a)?
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OpenStudy (xapproachesinfinity):
yes g(a)=2-3a
what about g(a-b) now
OpenStudy (xapproachesinfinity):
use the same function g(x)=2-3x
to find that
OpenStudy (anonymous):
2-3(a-b)?
OpenStudy (xapproachesinfinity):
yes good
OpenStudy (xapproachesinfinity):
now f(a)
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OpenStudy (anonymous):
2-3(a)-2-3(a-b)+3(a)+2-4/(a)?
OpenStudy (xapproachesinfinity):
that the next step let's not skip
do f(a) first
OpenStudy (xapproachesinfinity):
i mean you have the idea but that's wrong because of the sign
OpenStudy (anonymous):
3(a)+2-4/(a)
OpenStudy (xapproachesinfinity):
yes
now g(a)-g(a-b)-f(a)=2-3a-(2-3(a-b))+3a+2-4/a
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OpenStudy (xapproachesinfinity):
the difference btw what i just did and what you did
is i put those parenthesise before 2-3(a-b)
because of the sign that came before it
OpenStudy (xapproachesinfinity):
if ignored that it would be wrong
because the sign has to be distribute to 2-3(a-b)
OpenStudy (xapproachesinfinity):
so no what we do it open up the parenthesis
2-3a-2+3(a-b)+3a+2-4/a
OpenStudy (xapproachesinfinity):
we simplify more
=2-3a-2+3a-3b+3a+2-4/a
=....?
OpenStudy (xapproachesinfinity):
finish it up
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OpenStudy (anonymous):
oh okay, thanks so much!!
OpenStudy (xapproachesinfinity):
welcome!
OpenStudy (anonymous):
so is the final answer 3a-3b+2-4/a
OpenStudy (xapproachesinfinity):
yeah seems good!