check my answer
What is the slope of the line which passes through (1, 4) and (0, 1)? 3 -3 4 -2
\[\frac{ y_2 - y_1 }{ x_2 - x_1 } = \frac{ 1 - 4 }{ 0 - 1 } = \frac{ -3 }{ -1 }\]
so 3 is my choice
yep
Correct!
i have mote do you mind checking?
sure
NOT AT ALL!
whoops caps
yep that's right thanks for the work!
What is the 2nd term when 5y^3 + 2y - 3 + 6y^2 - y^4 is arranged in descending order? 5y^3 <--- my choice 2y 6y^2 -y^4
highest to lowest degree 5 ,4,3,2,1,constant
because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\]
Correct! The first is 6y^2, second your choice!
\(\color{blue}{\text{Originally Posted by}}\) @shinebrightlikeadimon because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\] \(\color{blue}{\text{End of Quote}}\) yep :-)
i meant +5y^3
okay thanks
Hey, would any of you mind helping me with my problem? It's for my homework this summer, and I'm trying to finish it so I can check it with my best friend whose taking the course.
Which of the following is the conjugate of a complex number with 4 as the real part and -3 as the imaginary part? -3 + 4i 3 - 4i 4 + 3i 4 - 3i
this one idk the answer to
4 is the real part and -3 is imaginary so \[\huge\rm 4 - 3\color{red}{i}\] conjugate change the sign of imaginary part
oh okay thnx
Given f(x) = (x - 7)/(3), solve for f-1(4). -1 19 <--- my choice 33 37
\[f(x) = \frac{ x - 7 }{ 3 } \] \[y = \frac{ x - 7 }{ 3 }\] \[x = \frac{ y - 7 }{ 3 }\] \[3x = y - 7 \] \[y = 3x + 7\] \[y = 3(4) + 7 \] \[12 + 7 + 19\]
yep right
yay
Factor 4x^2 - 4x - 24 completely. 4(x - 3)(x + 2) <--- my choice 4(x + 3)(x - 2) (4x + 3)(x - 2) (4x - 3)(x + 2)
i used a factoring calculator b/c idk how to factor on my own
first of all find GCF(greatest common factor )
4
yes right take it out 4(???????) divide all 3 terms by GCF which is 4 write your answer in the parentheses
x^2 - x - 6
sorry forgot to write them in parenthesis
\[\huge\rm 4(x^2 - x - 6)\] now find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term B abc are Ax^2 +Bx+C
idk 2 and 3
\[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\] remember there is invisible one 1x^2 so a= what c= ?
a = 1 and c = -6
yes right so a times c = ?
-6
yes so 2 times 3 is not equal to -6 which one should be negative 3 or 2 ? remember when you add or subtract them you should get middle term
\[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\] middle term is b which is -1
-3
ye right so bec leading coefficient is 1 that's why just both number with (x+ first number )(x +2nd number )
done!
thnx im going to practice it later to get better at it
great! gO_od luck!
thnx
What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)? (y - 8) = 2(x - 3) <-- my choice (y + 3) = -2(x + 4) (y - 2) = -2(x + 4) (y + 4) = 2(x + 3)
what is the general form of point slope ?
equation *
(y - y1) = m(x - x1)
yes right now pick one of order pair substitute y_1 and x_1 value
y + 4 = m(x +3)
yes right there is a negative sign in the formula and x and y values are also negative so it becomes positive 4 and 3 that's right
oh so D
yes
okay the next one idk
Simplify 2 times the 3rd root of 108 . 16 times the 3rd root of 18 8 times the 3rd root of 6 5 times the 3rd root of 4 6 times the 3rd root of 4
factor 108 one of number must be perfect cube root
what
what are factor of 108?
idk
start dividing 108 by 2
54,
do i devide 54 by 2 too?
yes right
|dw:1433717296775:dw| 54 is divisible by 2 so yes divide
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