Question

in an organic synthesis 62% yield of product is achieved. which of these conversions are consistent with this information
1) 74 g of butan-2-ol -> 44.64 g of butanone
2)74 g of butan-1-ol -> 54.56 g of butanoic acid
3) 74 g of 2-methylpropane-1-ol -> 54.56 g of 2-methylpropanoic acid

Answer 1

You have to try all of them individually, use the equation at the bottom.

Assuming that the coefficients for the reactants and products involved are 1...

\(\sf moles_R=moles_P\) sub in: \(\sf moles_R=\dfrac{mass_R}{Molar~mass_R}\)

\(\sf \dfrac{mass_R}{Molar~mass_R}=\dfrac{mass_P}{Molar~mass_P}\)

therefore: \(\sf mass_P= \dfrac{mass_R*Molar~mass_P}{Molar~mass_R}\)

this is the theoretical yield, since only 60% was made, multiply by 0.6. So,

\(\sf \large mass_P= 0.6*\dfrac{mass_R*Molar~mass_P}{Molar~mass_R}\)

Answer 2

For one i tried (74×72)/74 and then multiplied by 0.6 it gives 43.2. Where am i wrong?

Answer 3

hm idk, i tried them too didn't get any of the possible answers

Answer 4

And tomorrow's my exam :(

Answer 5

Ohhhh i'm so sorry it's not 60% it's 62% my apologies

Answer 6

ohh lol no worries

it should be the first or the second then

Answer 7

It's just i copied it from internet

Answer 8

All three of them are correct according to marking scheme

Answer 9

oh okay. double check them i suppose

Answer 10

There must be a typo or something :/

Answer 11

First two are correct the last one is creating problem now.

Answer 12

i get 54.53828 for the last one

Answer 13

No i got it correct yaaayyy

Answer 14

It was (0.62×74×88)÷74

Answer 15

awesome!