Question

help solving quadratic equation 8x+60=x^2+15x
Help please please cx

Answer 1

set it equal to 0
so move 8x+60 to the right side

Answer 2

so 0=x^2+15x- 8x+60?

Answer 3

nope 60 is positive at left side so subtract 60 both sides

Answer 4

ohhh so 0=x^2+15x- 8x-60?

Answer 5

yes right now combine LIKE terms

Answer 6

0=x^2+15x- 8x-60
^
7
0=x^2+7x-60

Answer 7

@Nnesha what do i do next?

Answer 8

yes that's right now you can use quadratic formula to solve for x \[\huge\rm \frac{ {- }b \pm \sqrt{b^2 -4ac} }{ {2a} }\]

or you can factor it
\[ \large\rm \color{red}{1}x^2 +\color{Red}{ 7}x \color{reD}{- 60} = 0\]\[\large\rm \color{blue}{A}x^2 +\color{blue}{B}x+\color{blue}{C}=0\]

Answer 9

the factoring one seems simpler lol

Answer 10

i think thats what im suppose to do, is to factor it

Answer 11

alright
to factor this one find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term b

Answer 12

A is leading coefficient
C is constant term :-)

Answer 13

-5 and 12

Answer 14

yep right
so bec leading coefficient is just one GREAT!
just write those two numbers with x
(x + 1st number)(x+ 2nd number)

Answer 15

(x+(-5))(x+12)

Answer 16

yes right + times -5
equal -
so (x-5)(x+12)=0

Answer 17

if you have to solve for x
set both parentheses equal to zero solve for x
like this
x-5 =0 and x+12 =0

Answer 18

ohh ok, i would get 5 and -12

Answer 19

yep that's right!

Answer 20

Thank you!, is that it?

Answer 21

the answer

Answer 22

yep
factors are (x-5)(x+12)
solution or x value are 5 and -12

Answer 23

Thank you so much! Cx

Answer 24

my pleasure :-)