Question

@jim_thompson5910

Answer 1

Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created?

f(x) = one eighth (x - 1)2 - 2
f(x) = -one eighth (x + 1)2 - 2
f(x) = -one sixteenth (x + 1)2 - 2
f(x) = one sixteenth (x - 1)2 + 2

Answer 2

@Nnesha

Answer 3

@misty1212

Answer 4

@timo86m

Answer 5

HI!!

Answer 6

no one likes these conic section problems, they are not that hard

Answer 7

parabola opens up, and the vertex is half way between \((1,6)\) and \(y=-2\) so it is at \((1,3)\)

Answer 8

general form will be
\[f(x)=\frac{1}{4p}(x-h)^2+k\] so you have \[f(x)=\frac{1}{4p}(x-1)^2+6\] all you need is \(p\)

Answer 9

\(p\) is the distance between the vertex and the focus (or the vertex and the directrix) which is 3, so final answer is
\[f(x)=\frac{1}{12}(x-1)^2+6\]