Find an equation of the tangent line to the curve at the given point.
y = sin 5x + sin^2 5x, (0, 0)
I got 5x but it was wrong
please help me

Question

Find an equation of the tangent line to the curve at the given point.
y = sin 5x + sin^2 5x,  (0, 0)
I got 5x but it was wrong
please help me

loser66 · Answer

y'= ??

anonymous · Answer

cos5x+2sin5x?

anonymous · Answer

Forgot chain rule.

loser66 · Answer

it's not that but I got what you have. hahahaha....

anonymous · Answer

$y' = cos(5x)\cdot5 +2sin(5x)\cdot cos(5x)\cdot5$
$y' = 5cos(5x) + 10sin(5x)cos(5x)$

loser66 · Answer

@Concentrationalizing  some more steps, you will get what he got and it is wrong (according to him) :)

loser66 · Answer

but I don't know how it is wrong!! or you should write y = 5x @gaba

anonymous · Answer

Plug in 0 into the derivative:
$y' = 5cos(0) + 10sin(0)cos(0)$
$y' = 5$

Hmm....question is typed incorrectly?

anonymous · Answer

i needed to type it as y=5x! thank you!!

anonymous · Answer

oh, lol. Okay, cool.

loser66 · Answer

hahahaha...................... it's fun.