Question

Find an equation of the tangent line to the curve at the given point.
y = sin 5x + sin^2 5x, (0, 0)
I got 5x but it was wrong
please help me

Answer 1

y'= ??

Answer 2

cos5x+2sin5x?

Answer 3

Forgot chain rule.

Answer 4

it's not that but I got what you have. hahahaha....

Answer 5

\(y' = cos(5x)\cdot5 +2sin(5x)\cdot cos(5x)\cdot5\)
\(y' = 5cos(5x) + 10sin(5x)cos(5x)\)

Answer 6

@Concentrationalizing some more steps, you will get what he got and it is wrong (according to him) :)

Answer 7

but I don't know how it is wrong!! or you should write y = 5x @gaba

Answer 8

Plug in 0 into the derivative:
\(y' = 5cos(0) + 10sin(0)cos(0)\)
\(y' = 5\)

Hmm....question is typed incorrectly?

Answer 9

i needed to type it as y=5x! thank you!!

Answer 10

oh, lol. Okay, cool.

Answer 11

hahahaha...................... it's fun.