Question

Would someone kindly give their help?
screencap in comments.

Answer 1

To solve this, you need to remember that when dividing powers of terms with the same base you need to subtract the indices. For example
\[\large \frac{w^{6} x^{4}}{w^{2} x^{3}}=w^{(6-2)}x^{(4-3)}=w^{4}x\]

Answer 2

I don't know how to do that :/

Answer 3

\[\large \frac{4x^{3} y^{4}}{-8xy^{2}}=\frac{4}{-8} \times x^{(3-1)}y^{(4-2)}=?\]

Answer 4

This is too complicated for me, can you help me break it down?

Answer 5

Can you subtract 1 from 3, and subtract 2 from 4?

Answer 6

2 and 2 so yes

Answer 7

Correct. And what is 4/-8?

Answer 8

-1/2

Answer 9

yeah, and what isare (3-1) ? , (4-2) ?

Answer 10

yeah you had 2 and 2, so...


\[\large \frac{4x^{3} y^{4}}{-8xy^{2}}\\
=\frac{4}{-8} \times x^{(3-1)}y^{(4-2)}\\
=\frac{-1}2x^2y^2\]

Answer 11

I don't get that :( I'm sorry I have a horrible instructor

Answer 12

What part don't you get? You have correctly answered the sections that were broken down for you.

Answer 13

The formatting makes my brain shut down

Answer 14

I don't get it

Answer 15

So the correct choice has -1/2, x^2 and y^2.

Answer 16

4x3y4/8xy2
Reduce the expression by cancelling the common factors.
More Steps
Factor 4 out of 4x3y4.

4(x3y4)−8xy2

Rewrite the expression.

x3y4−2xy2
x3y4−2xy2
Reduce the expression by cancelling the common factors.
More Steps
Factor x out of x3y4.

x(x2y4)−2xy2

Rewrite the expression.

x2y4−2y2
x2y4−2y2
Reduce the expression by cancelling the common factors.
More Steps
Factor y2 out of x2y4.

y2(x2y2)−2y2

Rewrite the expression.

x2y2/-2
x2y2/-2
Move the negative in front of the fraction.
−x2y2/2

Answer 17

Thank you all so much. I get it so much more now.

Answer 18

You're welcome :)