Question

PLEASE HELP

Answer 1

\[\frac92\log_2(x)=9\]
multiply both sides by 2/9,
to get rid of that fraction on the left hand side

Answer 2

so 5.3399?

Answer 3

i entered it and its wrong

Answer 4

\[\frac92\log_2(x)=9\\
\frac29\times\frac92\log_2(x)=\frac29\times9\\
\cdots=\cdots\]

Answer 5

can you simplify both sides now?

Answer 6

log2(x)=1?

Answer 7

you've got the left hand side right, but check that right hand side again

Answer 8

Im not sure what i did wrong

Answer 9

\[\frac29\times9=\frac2{\cancel 9}\times\cancel 9\]

Answer 10

log2(x)=2?

Answer 11

right !

now we use the definition of a log

\[\log_b a = c\iff a=b^c\]

Answer 12

log2 (2) = 1?

Answer 13

you had

\[\log_2(x) = 2\]

so

\[x = . . . \]

Answer 14

im so confused

Answer 15

\[\log_b(a) = c\iff a=b^c\]
\[\log_2(x) = 2\iff x=?^{??}\]

Answer 16

2

Answer 17

what is the final equation

x =

Answer 18

i dont know!! how do i fnid log2(x)=2

Answer 19

Use the definition


for example


\[\log_{10}(A) = 3 \iff A = 10^3 = 1000\]

Answer 20

ohhhh 4?

Answer 21

yeah that is the final answer for x

Answer 22

i dont get it, the computer says its .25

Answer 23

it's probably due to the confusion of the regular 2 being typed out and the subscript 2... .25 = 1/4 . so the computer claims that it's 1/4 -> .25?!

Answer 24

oh it is meant to equal -9 not 9

Answer 25

whoops

Answer 26

lol latex typo

Answer 27

\[\frac92\log_2(x)=-9\\
\frac29\times\frac92\log_2(x)=\frac29\times-9\\
\cdots=\cdots\]

Answer 28

I see ... \[\log_2(x) = -2\]

Answer 29

\[\log(x) = 2^{-2}\]
\[\frac{1}{2^2} \rightarrow \frac{1}{4}\]

Answer 30

ohhhhh makes sense

Answer 31

also known as .25 in decimal form

Answer 32

(sorry bout that @Polkapen )

Answer 33

i have one more question

Answer 34

I'm about to faint...sorry I have yet to eat dinner. ~_~

Answer 35

oh ok