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When 2.0 A of current moves across a 1.0 MΩ resistor, then what is the drop in voltage (∆V) across the resistor? A. 2.0 × 10^0 V B. 2.0 × 10^2 V C. 2.0 × 10^3 V D. 2.0 × 10^6 V
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here we have to apply the Ohm's law: \[\Delta V = RI = 2 \times 1 \times {10^6}\]
since 1MOhm= 10^6 Ohms
ohh ok! so we get choice D as our solution?
is that correct? :)
that's right!
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yay! thanks!
:)
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