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1. How many milliliters of a 6.00 molar hydrochloric acid (HCl) solution would be needed to react completely with 100.0 grams of Iron metal? 2Fe (s) + 6HCl (aq) yields 2FCl3 (aq) + 3H2 (g) 196 ml 293 ml 896 ml 317 ml 2. How many grams of calcium chloride would form if 1.25 liters of a 2.50 molar hydrochloric acid (HCl) solution reacts with 1.10 liters of a 2.25 molar calcium hydroxide Ca(OH)2 solution? 2HCl (aq) + Ca(OH)2 (aq) yields CaCl2 (aq) + H2O (l) 173 g 275 g 429 g 858 g
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