Question

1. How many milliliters of a 6.00 molar hydrochloric acid (HCl) solution would be needed to react completely with 100.0 grams of Iron metal?

2Fe (s) + 6HCl (aq) yields 2FCl3 (aq) + 3H2 (g)

196 ml
293 ml
896 ml
317 ml


2. How many grams of calcium chloride would form if 1.25 liters of a 2.50 molar hydrochloric acid (HCl) solution reacts with 1.10 liters of a 2.25 molar calcium hydroxide Ca(OH)2 solution?

2HCl (aq) + Ca(OH)2 (aq) yields CaCl2 (aq) + H2O (l)

173 g
275 g
429 g
858 g

Answer 1

@Australopithecus

Answer 2

@Abhisar

Answer 3

@tbeneka

Answer 4

@ayeshaafzal221

Answer 5

HEY AUSSIE

Answer 6

HEY TBENEKA

Answer 7

@Abhisar!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 8

Ok, let's start with question #1

Answer 9

Abhisar has this I will be here though still if he has to leave idk

Answer 10

well he left

Answer 11

First you will have to calculate how many moles of HCl is required.

Answer 12

Thanx @Australopithecus

Answer 13

nowhere*

Answer 14

From the equation we can see that 2 moles of Iron need 6 moles of HCl i.e (2*56) grams of iron need 6*(35.5+1) grams of HCl. Right?

Answer 15

yes

Answer 16

ok, i'll let @tbeneka proceed. Don't want to confuse.

Answer 17

5.373

Answer 18

@abhisar I keep getting 116 ml.. though? What did you get?

Answer 19

@Australopithecus

Answer 20

@WhirlwindSprint

Answer 21

@ganeshie8

Answer 22

well can u do the next question, then?

Answer 23

ya let me work it out first to see if I get an answer first rather than confusing you again.

Answer 24

ok np

Answer 25

im not much help in chemistry. mostly history for me but i'll give it a try.

Answer 26

Okay I actually got this one(sorry about messing up the first one)

Answer 27

i got 173 is that correct

Answer 28

Yup that's exactly what I got . Good job :D

Answer 29

I just got 173... so I guess so.