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A 10.0 Ω resistor is in parallel with a 30.0 Ω resistor and supplied by a 45.0 V battery. What is the total current drawn from the battery? A. 0.003 A B. 1.10 A C. 6.00 A D. 338 A
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here the total resistance is: \[\Large R = \frac{1}{{\frac{1}{{10}} + \frac{1}{{30}}}} = ...\]
7.5?
ok! so the requested current is: \[\Large I = \frac{{\Delta V}}{R} = \frac{{45}}{{7.5}} = ...amperes\]
6! so our solution is choice C? 6.00 A?
that's right!
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yay! thanks!:D
:)
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