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A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.0 V battery. What is the current passing through the 20.0 Ω resistor? A. 0.45 A B. 0.90 A C. 1.35 A D. 6.00 A
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here we have to apply the Ohm's law, so we can write: \[\Large {I_2} = \frac{{\Delta V}}{{{R_2}}} = \frac{9}{{20}} = ...Amperes\]
0.45? so our solution is choice A?
yes! correct!
yay! thank you!! okay last one :)
:)
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