Question

please help, question below

Answer 1

You need to know these rules of logs:

\(\Large \log_b \dfrac{x}{y} = \log_bx - \log_b y\)

\(\Large \log_b x^n = n \log_b x\)

Use the first rule first. What do you get?

Answer 2

so that means that in the second part of the equation, it always has to be subtracting... okay. that takes 2 answers off my list.

Answer 3

@mathstudent55

Answer 4

@mathstudent55

Answer 5

would it be \[\log_{4}8-2\log_{4}x \]

Answer 6

someone please help me

Answer 7

@Luigi0210

Answer 8

You're doing just fine.

Answer 9

did i get the right answer??:D

Answer 10

@radar

Answer 11

Yea you're right :_

Answer 12

No, that would be dividing 8 squared by c

Answer 13

I mean *x lol

Answer 14

Look at the earlier post by mathstudent55, you are supposed to be subtracting the divisor.

Answer 15

Did you choose D "did i get the right answer??:D"

Answer 16

no, thats a super smiley face, haha. i choose C and it was correct

Answer 17

O..K that is correct!

Answer 18

Applying the first rule we get:

\( \Large \log_4 \dfrac{8}{x^2} = \log_4 8 - \log_4 x^2\)

Applying the second rule we get:

\( \Large \log_4 \dfrac{8}{x^2} = \log_4 8 - 2 \log_4 x\)

Answer 19

You are correct.
Good job!

Answer 20

Sorry about that I guess I am not "hip" to internet speak lol.

Answer 21

I thought you were on track that is why I said you are doing fine, then you posted that and it threw me off.

Answer 22

@mathstudent55 Just a problem in "internet slang"