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OpenStudy (barrelracing):
suppose y varies directly with x. write a direct variation equation the relates x and y. then find the value of y when x =16
y=5 when x=2
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rishavraj (rishavraj):
For direct variation
y = kx
k is the propotionality constany
OpenStudy (barrelracing):
@bry856
jimthompson5910 (jim_thompson5910):
y = k*x
y = k*2 ... replace x with 2
5 = k*2 ... replace y with 5
solve for k to get k = _________ (fill in the blank)
rishavraj (rishavraj):
After getting k ...plug the value of k and x in the equation and get y
OpenStudy (barrelracing):
y=40
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jimthompson5910 (jim_thompson5910):
you should have found that k = 2.5
y = 2.5x
when x = 16, y = 2.5*16 = 40
so you have the correct y value
OpenStudy (barrelracing):
how do I find the direct variation that related x and y?
jimthompson5910 (jim_thompson5910):
what do you mean?
OpenStudy (barrelracing):
it says write a direct variation equation that relates x and y. this is still the same problem.
jimthompson5910 (jim_thompson5910):
so it just wants the equation with x and y in it
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jimthompson5910 (jim_thompson5910):
the k will be replaced with the numeric value you found
OpenStudy (barrelracing):
so y=40x?
jimthompson5910 (jim_thompson5910):
So you can either say \[\Large y = \frac{5}{2}x\] or \[\Large y = 2.5x\]
jimthompson5910 (jim_thompson5910):
I started with y = kx
then replaced k with 5/2 or 2.5
OpenStudy (barrelracing):
ohh ok I get it now thank you
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jimthompson5910 (jim_thompson5910):
np
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