suppose y varies directly with x. write a direct variation equation the relates x and y. then find the value of y when x =16 y=5 when x=2
For direct variation y = kx k is the propotionality constany
@bry856
y = k*x y = k*2 ... replace x with 2 5 = k*2 ... replace y with 5 solve for k to get k = _________ (fill in the blank)
After getting k ...plug the value of k and x in the equation and get y
y=40
you should have found that k = 2.5 y = 2.5x when x = 16, y = 2.5*16 = 40 so you have the correct y value
how do I find the direct variation that related x and y?
what do you mean?
it says write a direct variation equation that relates x and y. this is still the same problem.
so it just wants the equation with x and y in it
the k will be replaced with the numeric value you found
so y=40x?
So you can either say \[\Large y = \frac{5}{2}x\] or \[\Large y = 2.5x\]
I started with y = kx then replaced k with 5/2 or 2.5
ohh ok I get it now thank you
np
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