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Mathematics 9 Online
OpenStudy (anonymous):

Any one out there who can give me a hand doing integrals

OpenStudy (empty):

\(\int\)ure, I can help probably.

OpenStudy (anonymous):

\[\int\limits_{?}^{?} \sin2x/1+\cos^2x\]

OpenStudy (anonymous):

In class, my teacher said to make the denominator = to u or p

OpenStudy (anonymous):

so let p= 1+cos^2x

OpenStudy (anonymous):

dp =?

OpenStudy (anonymous):

Yeah, let the bottom be your u. You will need an identity on the numerator to get the proper cancellation, though.

OpenStudy (anonymous):

Take the derivative of p to get dp. Use the identity for the numerator sin 2x = 2 cos x sin x

OpenStudy (anonymous):

where did you find the identity?

OpenStudy (anonymous):

that's a double angle identity

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

can you give a hint on how to get dp

OpenStudy (anonymous):

It's going to be the derivative of 1 + cos² x. Use the chain rule

OpenStudy (anonymous):

is it -2cosxsinx?

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

with dx at the end?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

cool, but why? this is the stuff the confuses me

OpenStudy (anonymous):

ohhhhhhhhhhhh

OpenStudy (anonymous):

because there isn't an easy rule to integrate the original problem, so we use the substitution to make it simpler

OpenStudy (anonymous):

u r the man

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

The pic of Ernie is right on point too

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