Mathematics
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OpenStudy (anonymous):
Any one out there who can give me a hand doing integrals
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OpenStudy (empty):
\(\int\)ure, I can help probably.
OpenStudy (anonymous):
\[\int\limits_{?}^{?} \sin2x/1+\cos^2x\]
OpenStudy (anonymous):
In class, my teacher said to make the denominator = to u or p
OpenStudy (anonymous):
so let p= 1+cos^2x
OpenStudy (anonymous):
dp =?
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OpenStudy (anonymous):
Yeah, let the bottom be your u. You will need an identity on the numerator to get the proper cancellation, though.
OpenStudy (anonymous):
Take the derivative of p to get dp. Use the identity for the numerator sin 2x = 2 cos x sin x
OpenStudy (anonymous):
where did you find the identity?
OpenStudy (anonymous):
that's a double angle identity
OpenStudy (anonymous):
oh
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OpenStudy (anonymous):
can you give a hint on how to get dp
OpenStudy (anonymous):
It's going to be the derivative of 1 + cos² x. Use the chain rule
OpenStudy (anonymous):
is it -2cosxsinx?
OpenStudy (anonymous):
yes it is
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OpenStudy (anonymous):
with dx at the end?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
cool, but why? this is the stuff the confuses me
OpenStudy (anonymous):
ohhhhhhhhhhhh
OpenStudy (anonymous):
because there isn't an easy rule to integrate the original problem, so we use the substitution to make it simpler
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OpenStudy (anonymous):
u r the man
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
The pic of Ernie is right on point too