Question

Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x−3, y+4) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

Answer 1

@ganeshie8

Answer 2

To get the coordinates of transformed image, `subtract 3 from each x coordinate` and `add 4 to each y coordinate`

Answer 3

A = (−2, 2)

becomes

A' = (−2\(\color{Red}{-3}\), 2\(\color{Red}{+4}\)) = (-5, 6)

Answer 4

similarly see if you can find the new coordinates of remaining vertices

Answer 5

oh ok so for
A=(-5,6)
B= (-5,0)
C=(5,0)
D=(5,6)

Answer 6

@ganeshie8

Answer 7

doesn't look correct
try again

Answer 8

keep in mind, the transformation is \((x-3, y+4)\)

so you need to subtract 3 from x coordinate
and add 4 to y coordinate

Answer 9

oh ok
A= (-5,6)
B= (-1,8)
C= (1,8)
D=(1,6
@ganeshie8 im to sure if this is right sorry im trying my best

Answer 10

I dont know if I did It right or not

Answer 11

@ganeshie8 please please help me

Answer 12

Hey sry im back
still here ?

Answer 13

yea im still here

Answer 14

you should get
A' = (-5, 6)
B' = (-5, 8)
C' = (-1, 8)
D' = (-1, 6)

Answer 15

oh ok thank you so much im really sorry for all the trouble, but I have one last question can you Describe what characteristics you would find if the corresponding vertices were connected with line segments.

Answer 16

The line segments formed by joining corresponding vertices will be parallel because they all will be having the same slopes

Answer 17

What are you having trouble with he seems that he helped you