Question

Simple question. But trick involved. A ball is thrown horizontally from the top of a 10 meter high builiding. It strikes the ground at an angle of 30 degree. with what speed was it thrown?

Answer 1

@Miracrown

Answer 2

@ganeshie8

Answer 3

was the angle with respect to ground ?

Answer 4

Is it 20√6m/s

Answer 5

thrown horizontally means angle was 90 degree

assuming no drag force , so the horizontal velocity is constant call it V0
and the vertical velocity is Vy =zero
so the final vertical velocity is
\[V _{T}^{2}-V_{y}^{2} = 2 g h\]
thus you have vy

so
\[\tan 30 = \frac{ V _{0} }{ V _{y} }\rightarrow V _{0}= V _{y}* \tan30\]
just plug in numbers