Question

What is the 5th term of an arithmetic sequence if t2 = -5 and t6 = 7?

Answer 1

\[t_6-t_2=(6-2)d\]
where \(d\) is the common difference between consecutive terms.
\[7-(-5)=4d~~\implies~~d=\frac{12}{4}=3\]
You have \(t_6-t_5=d\), or \(7-3=t_5\).

Answer 2

So the answer is 4?

Answer 3

Yes

Answer 4

Thank you! <3