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In this circuit, which resistor will draw the least power? will draw inside!! A. R_1 B. R_2 C. R_3 D. the power will be the same for each resistor
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|dw:1433868602092:dw|
here the current is: I=12/(2.2+1.1+2.7)=...amperes
2!
ok!
now the power dissipated by R_1 is: P_1= R_1 * I^2= 2.2* 4=...
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8.8!
ok! the power dissipated by R_2, is: P_2= R_2 I^2 = 1.1* 4=...watts
4.4!
ok! finally the power dissipated by R_3, is: P_3 = R_e*I^2 = 2.7*4=...watts
oops.. P_3= R_3* I^2
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10.8!
ok! reassuming, we have these dissipated powers: P_1=8.8 watts, P_2=4.4 watts P_3=10.8 watts which is the littlest value among them?
P2! so is choice B our solution?
correct!
yay!! thanks!:)
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