Ask
your own question, for FREE!
Ask question now!
Mathematics
4 Online
OpenStudy (anonymous):
WILL GIVE MEDAL!
Find the value of x such that the data set has the given mean.
3.8, 4.2, 5.3, x; mean 4.8
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amoodarya):
\[4.8=\frac{3.8+4.2+5.3+x}{4}\]you can find x
11 years ago
OpenStudy (anonymous):
@amoodarya so would it be 3.325?
11 years ago
OpenStudy (anonymous):
@amoodarya x= 3.325?
11 years ago
OpenStudy (amoodarya):
i think so
11 years ago
OpenStudy (amoodarya):
no
it is not
x=4(4.8)-5.3-4.2-3.8=5.9
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
5.9 is correct
11 years ago
OpenStudy (anonymous):
@welshfella could you explain to me how you get 5.9? I'll give you a medal
11 years ago
OpenStudy (amoodarya):
\[4.8=\frac{3.8+4.2+5.3+x}{4}\\\frac{4.8}{1}=\frac{3.8+4.2+5.3+x}{4}\\4.8 *1=3.8+4.2+5.3+x\\\]
11 years ago
OpenStudy (welshfella):
first you cross multiply
4 * 4.8 = 19.2
so
3.8 + 4.2 + 5.3 + x = 19.2
adding the numbers on the left
13.3 + x = 192
now subtract 13.3 from both sides (this will leave x on its own on left side)
13.3 + x = 19.2
- 13.3 - 13.3
x = 5.9
11 years ago
OpenStudy (welshfella):
cross multiply:-
|dw:1433875265692:dw|
-
11 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question
Latest Questions
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals