In the circuit shown, a voltage drop of 6.6 V wil occur across which of the following resistors?
A. R_1
B. R_2
C. R_3
D. R_4
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OpenStudy (anonymous):
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OpenStudy (michele_laino):
here we have to compute the total or equivalent resistance
OpenStudy (michele_laino):
the equivalent resistance is given by the subsequent formula:
\[\Large {R_{EQ}} = 8.5 + 3.2 + \frac{1}{{\frac{1}{{13}} + \frac{1}{{18}}}} = ...\Omega \]
OpenStudy (anonymous):
so we get 19.248?
OpenStudy (michele_laino):
ok! we can assume R_eq=19.25 ohms
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OpenStudy (michele_laino):
so the total current is:
I=15/19.24=...amperes
OpenStudy (anonymous):
and we get 0.779?
OpenStudy (michele_laino):
ok! I=0.779 amperes.
Now the voltage drop of resistor R_1 is:
V_1=8.5*0.779=...volts
OpenStudy (anonymous):
6.6215!
OpenStudy (michele_laino):
ok! maybe it is the right answer
the voltage drop of resistor #4, is:
V_4=3.2*0.779=...volts
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OpenStudy (anonymous):
2.4928!
OpenStudy (michele_laino):
ok!
OpenStudy (michele_laino):
now the voltage drop V_AB is:
15-(6.6215+2.4928)=...volts
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