Question

Medal + fan
Simplify the expression.

x times the square root of the quantity 8 x cubed, plus x times the square root of 2, plus four times the square root of the quantity 2x

Answer 1

\[x \sqrt{8x ^{3}} + x \sqrt{2} + 4\sqrt{2x}\]

Answer 2

I'm usually good at math but this question is a little confusing....
So far I think the answer is 2 because yo can simplify it to get 2x^2sqrt(2x)... and so on

Answer 3

\[2\sqrt{2} \times x \times x ^{3/2} + x \times \sqrt{2} + 4 \sqrt{2} \times x^{1/2} \]

Answer 4

To write it into its raw exponential form.

Answer 5

why did you put fractions in the radical?

Answer 6

By putting the exponents in their fraction forms, you can clearly see their combined values.

Answer 7

This will allow you to factor out an exponential of x, through subtraction of the exponent.

Answer 8

As you can see in this question, the lowest "factorable" term is \[\sqrt{x}\]

Answer 9

I'm only in ninth grade, I don't think this is necessary.. besides, I haven't learned this yet.

Answer 10

I'm not looking for the lowest factorable term.... I'm looking for the leading coefficient when it's in simplified form

Answer 11

But it's factored form looks something like this: \[\sqrt{2} \sqrt{x} (4+\sqrt{x}+2 x^2)\]

Answer 12

To do that, you need write out the terms in full and subtract the exponents when factoring.

Answer 13

I think we're looking for the simplified form not the factored form... \[2x^2 \sqrt{2x} + x \sqrt{2} + 4 \sqrt{2x}\]

Answer 14

Is this fully simplified?

Answer 15

Well, I suppose you can't go any further to "simplify" it without factoring.

Answer 16

ok, so we agree that the leading coefficient is 2?

Answer 17

Okay, thanks, I got it right!

Answer 18

The leading coefficient of the entire term is not 2, its \[2\sqrt{2}\]

Answer 19

100% on my quiz! woot!

Answer 20

Great to hear!

Answer 21

Well, I guess it was the answer they were looking for!

Answer 22

As promised... medal and fan....