Question

What is the total number of N, H, and O atoms in 0.956 mol of ammonium nitrate, NH4NO3, an important fertilizer? anyone able to help please?

Answer 1

There's 6.022 x 10^23 molecules in one mole. So since there's 0.956 moles of ammonium nitrate, we want to find the number of molecules. So multiply 0.956 by avagodro's # (6.022 x 10^23).
After you get the number of molecules, to find the total # of N, H, and O atoms, just multiply that number by how many of the elements there are. So since there's 2 nitrogen in ammonium nitrate, you would multiply 2 by the answer you got previously.
And you do the same thing to find for hydrogen and oxygen.