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Pleaseeeeeeee help i'm drowning in confusionnnnnnn
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\[(\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\]
2^-n or (2/3)^-n ?
2 to the -n power or 2/3 to the -n which one is it ?
it's inside the parantheses
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2 to the -n
oh alright so \[\huge\rm (\frac{ 2 }{ 3 }^{-n}) (\frac{ 3 }{ 2 }^{-n}) = \frac{ 1 }{ 36 }\] there are negative exponent so apply exponent rule \[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\] flip the fraction
i cant do |dw:1433890169161:dw|
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