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Choose the counterexample that disproves the conjecture? If a perfect square is odd, then its square root is multiple of 3. 4 9 25 81
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Well all these choices are perfect squares...so we only want odd here so 4 is out Now...we can see 9 is divisible by 3 we can see that 81 is divisible by 3 is 25 divisible by 3?
no
Right the square root of 25 is 5 which is definitely not a multiple of 3...and that would be your counterexample!
thanks
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