Question

The Jones family attends a movie for $47.00 with two adults and three kids. The Smith family attends when some friends are in town for $74.75 with three adults and five kids. How much does the Ramirez family have to pay with adults and four kids

Answer 1

set up some equations

Answer 2

what kind??

Answer 3

Jones family:

2*adults + 3*kids = $47 total

2*a + 3*k = 47

2a + 3k = 47

Answer 4

all three of those equations represent the same thing

Answer 5

can you set up an equation for the Smith family now?

Answer 6

3a+5k=74.75
whats next?? @bi

Answer 7

perfect now you have two equations and two unknowns, can you solve this system for a and k?

2a + 3k = 47

3a + 5k = 74.75

Answer 8

how do you do that? sorry

Answer 9

are you allowed to use a calculator on tests?

Answer 10

no

Answer 11

hmm ok, the easiest way would be either elimination or substitution, which do you prefer?

Answer 12

substitution

Answer 13

what is the last sentence supposed to say? "How much does the Ramirez family have to pay with adults and four kids"

Answer 14

its missing the number of adults

Answer 15

with four adults and four kids

Answer 16

a. y=45+3k?

Answer 17

ok solve one of those 2 equations for either a or k, you choose

Answer 18

hmm close but not quite

Answer 19

2a + 3k = 47, lets solve for a, so first subtract 3k from both sides

Answer 20

2a = 47 - 3k, now divide both sides by 2

Answer 21

22

Answer 22

no, a = (47 - 3k) / 2

Answer 23

do you understand?

Answer 24

and what will be the answer

Answer 25

to the whole problem?

Answer 26

just to the first one

Answer 27

we are working on it

Answer 28

do you understand how we got a = (47 - 3k) / 2

Answer 29

yes

Answer 30

ok so now you know the value of a, we cannot plug it back into the same equation because we will not get any new information, so lets plug it into the other equation

Answer 31

can you please plug what we found for a, into the other equation?

Answer 32

3a=74.75-5k

Answer 33

thats true but you need to plug what we found for a into that equation

Answer 34

so that we can solve for k

Answer 35

can u plug it in.. I'm kinda lost

Answer 36

ok lets start again, because me doing it for you wont help anyone

Answer 37

we have these two equations that we came up with

2a + 3k = 47

3a + 5k = 74.75

Answer 38

we looked at the first equation and solved for a

2a + 3k = 47

2a = 47 - 3k

a = (47 - 3k) / 2

Answer 39

now we plug that value for a, into the second equation

3a + 5k = 74.75

3(plug in here) + 5k = 74.75

Answer 40

go for it

Answer 41

3(47-3k)+5k=74.75

Answer 42

thats very close but you left out the divide by 2, i will put it in for you

3((47-3k)/2)+5k=74.75

Answer 43

$$3*\frac{47-3k}{2} + 5k = 74.75$$

Answer 44

now you need to solve that for k

Answer 45

by the way elimination method would have been much easier, but thats ok this is good practice

Answer 46

so solve that for k and what do you get for k?

Answer 47

im not sure how you do it

Answer 48

maybe it will help to write (47 - 3k) / 2 as separate fractions, can you do that?